I have a 4 x 8 with an oval track running the perimeter. I want a figure 8 in the center using 18 radius track. what angle cross do I need at the center? and can I in fact fit the figure 8 inside the current 4 x 8 oval?
90* angle.
If the two are going to be seprate loops, just be sure to fit a straight piece at the ends of the outer loop, so that the outer oval is now more of a rectangle.
OR use 22R curves for the outer loop.
Either way it should be a tight fit.
IF this is what you have in mind, or something like this one
http://www.trainsetsonly.com/page/TSO/PROD/150-HO10 you should be OK
IF this
http://www.trainsetsonly.com/page/TSO/PROD/150-HO11
you have a some wiring to do,,the above forms a reverse loop.
Dear James:
Quote from jward:
"60 degree crossing......42" x 84"....20(ea.18"R) curves, 4(ea.) 9" straights, 1(ea.) 60 degree crossing"
Trust me, 60 degrees makes the most usable/flexible Figure-8.
It's the only crossing that puts the curve track joints on the compass points (N, E, S, W).
Try it on CAD first.
Download and use Anyrail.com layout CAD program. Fun and easy to learn. First 50 track pieces are free.
Hope this helps.
Sincerely,
Joe Satnik