Hello, forgive my ignorance, but I need to know how big an oval layout would be using 35.5 radius curves? Thanks in advance for your replies. P.s. Is there an equation that can be utilized for this type question, I.e. Figuring out layouts using different sized radius curves?
If only utilizing curved track and no straight track, the minimum space required would be approximately 78 inches by 78 inches or 6 & 1/2 feet by 6 & 1/2 feet, allowing slightly more room on the edges incase of a derailment would require a space of 84 inches by 84 inches or 7 feet by 7 feet. Adding straight track will add to the required space.
TD51,
Radius is to the center-line of the track, and Bachmann HO E-Z Track track bed is very close to 2" wide.
Twice radius plus a track bed width = the (outside edge to opposite outside edge) width of your circle.
So, 2 x 35.5" + 2" TBW = 73"
As a rule of thumb, I allow an extra TBW for outside overhang, so 75" fence-to-fence.
Hope this helps.
Sincerely,
Joe Satnik