Dear Mr. Bachmann,
Referring to Mr. Scot Lawrence's 29n2 article,
https://scotlawrence.github.io/29n2/index.html
S Gauge track = 7/8 " or 22.43 mm
0 Gauge track = 1 1/4 " or 32 mm ( 3 foot Gauge ) * 2/3 = 21.33 mm
The ratio of 0 Gauge : S Gauge = The ratio of three foot gauge : two foot gauge.
At the scale of 1/28.5 ,
1 Gauge track at 44.45 mm * 28.5 = 1266.825 mm = 49.875 inch
4' 8 1/2" = 56.5 inch
56.5 inch - 49.875 inch = 6.625 inch = that is 6 5/8 inch too narrow track
0 Gauge track at 32 mm * 28.5 = 912 mm = 35.91 inch , that is 0.09 inch too narrow track
S Gauge track at 22.43 mm * 28.5 = 639.255 mm = 25.17 inch , that is 1.17 inch too wide track
Inline image
http://www.oscalekings.org/images/model_sizes.jpg
Clearly Scot's idea of 1/29 Scale should be adopted by large scale manufactures as 1 Gauge track currently represents 4' 8 1/2" , 0 Gauge track would represent 3 foot gauge and S Gauge track would represent 2 foot gauge.
Norman
Realize - A 1:20.3 scale model built to run on 45 mm (Gauge 1) track -- the track represents three foot gauge.
Norman,
Check these threads on scale/gauge
http://www.bachmanntrains.com/home-usa/board/index.php/topic,32669.0.html
http://www.bachmanntrains.com/home-usa/board/index.php/topic,27396.0.html
Bob C