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Williams by Bachmann
12 VOLT BAYONET BASE LAMP QUESTIONS
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Topic: 12 VOLT BAYONET BASE LAMP QUESTIONS (Read 11471 times)
DominicMazoch
Re: 12 VOLT BAYONET BASE LAMP QUESTIONS
«
Reply #15 on:
May 12, 2010, 07:11:50 PM »
The 24 V might have more resistance, but the difference would be so small I don't think it is going to a big difference.
I used a 28 V bulb on an O22 switch, and it seemed to work. A 14 V bulb runs so hot I was worried it would melt the lantern.
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Joe Satnik
Re: 12 VOLT BAYONET BASE LAMP QUESTIONS
«
Reply #16 on:
May 13, 2010, 10:33:49 AM »
Dom,
How did you power your O22 switches? If constant power, not track power, what was the voltage that you used?
Lee,
Perhaps I should rephrase my previous question on lamp resistance.
Start with an original lamp.
If you wanted to design a new lamp that would use the same amount of electrical power, yet be supplied with twice the voltage, how would the resistances of the original ( = Ro ) and new ( = Rn ) lamp filaments compare?
Hint: Use equation P = V x V/R,
Hope this helps.
Sincerely,
Joe Satnik
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If your loco is too heavy to lift, you'd better be able to ride in, on or behind it.
DominicMazoch
Re: 12 VOLT BAYONET BASE LAMP QUESTIONS
«
Reply #17 on:
May 13, 2010, 10:10:57 PM »
I use about 14 V on the side plug on the switch.
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Joe Satnik
Re: 12 VOLT BAYONET BASE LAMP QUESTIONS
«
Reply #18 on:
May 14, 2010, 12:00:39 PM »
Using algebra,
Po = Pn Original power same as new power.
Po = Vo x Vo/Ro power is V squared over R
Vn = 2 x Vo New voltage is twice original
Pn = 2Vo x 2Vo/Rn = Po = Vo x Vo/Ro substitute
4 x Vo x Vo/Rn = Vo x Vo/Ro combine twos
4/Rn = 1/Ro divide out (cancel) Vo squared from both sides
1 x Rn = 4 x Ro Cross multiply
Rn = 4 x Ro Drop 1 x (redundant)
So, same electrical power, @ twice the voltage and half the current, the resistance is quadrupled. (X 4)
Hope this helps.
Sincerely,
Joe Satnik
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If your loco is too heavy to lift, you'd better be able to ride in, on or behind it.
Joe Satnik
Re: 12 VOLT BAYONET BASE LAMP QUESTIONS
«
Reply #19 on:
May 14, 2010, 12:12:29 PM »
Dom,
What are the O22 lamp part numbers, 28 and 14 volt?
Joe Satnik
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If your loco is too heavy to lift, you'd better be able to ride in, on or behind it.
DominicMazoch
Re: 12 VOLT BAYONET BASE LAMP QUESTIONS
«
Reply #20 on:
May 16, 2010, 11:37:52 PM »
Right now i am using a Shack bulb. Only problem is the bulb is taller than the usual O22 bulb.
But Lionel did sell a line of replacement bulbs for 18 volts because of TMCC/L. That might be a source.
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phillyreading
Re: 12 VOLT BAYONET BASE LAMP QUESTIONS
«
Reply #21 on:
May 17, 2010, 12:13:12 PM »
Quote from: Joe Satnik on May 14, 2010, 12:00:39 PM
Using algebra,
Po = Pn Original power same as new power.
Po = Vo x Vo/Ro power is V squared over R
Vn = 2 x Vo New voltage is twice original
Pn = 2Vo x 2Vo/Rn = Po = Vo x Vo/Ro substitute
4 x Vo x Vo/Rn = Vo x Vo/Ro combine twos
4/Rn = 1/Ro divide out (cancel) Vo squared from both sides
1 x Rn = 4 x Ro Cross multiply
Rn = 4 x Ro Drop 1 x (redundant)
So, same electrical power, @ twice the voltage and half the current, the resistance is quadrupled. (X 4)
Hope this helps.
Sincerely,
Joe Satnik
Joe,
I am totally lost when it comes to algebra! I may know some geometry but that is about it, mainly basic math. Also I think that you are trying to describe an electronic circuit and how it works rather than a basic electric circuit.
Basically when you increase resistance in a circuit you increase the power consumed. So the point that I was trying to get across is that a lower volt light bulb should let you have more power to the motor, this will be noticed with a lower watt transformer.
Lee F.
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Joe Satnik
Re: 12 VOLT BAYONET BASE LAMP QUESTIONS
«
Reply #22 on:
May 17, 2010, 12:33:20 PM »
Lee,
You said:
"Basically when you increase resistance in a circuit you increase the power consumed."
No, just the opposite.
Power = V x V / R
If the Voltage on a load stays the same, and its resistance increases, the power decreases.
/R means "divide by R".
Hope this helps.
Joe Satnik
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If your loco is too heavy to lift, you'd better be able to ride in, on or behind it.
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